c) \(16-x^2+2xy-y^2=\left(4-x+y\right)\left(4+x-y\right)\)
d) \(\left(x-1\right)^2-4\left(2x-3\right)^2=\left(5-3x\right)\left(5x-7\right)\)
e) \(x^3-3x^2+3x-1=\left(x-1\right)^3\)
e) \(x^2-7=\left(x-\sqrt{7}\right)\left(x+\sqrt{7}\right)\)
c) \(16-x^2+2xy-y^2=\left(4-x+y\right)\left(4+x-y\right)\)
d) \(\left(x-1\right)^2-4\left(2x-3\right)^2=\left(5x-7\right)\left(5-3x\right)\)
e) \(x^3-3x^2+3x-1=\left(x-1\right)^3\)
f) \(x^2-7=\left(x-\sqrt{7}\right)\left(x+\sqrt{7}\right)\)
c. \(16-x^2+2xy-y^2=16-\left(x^2-2xy+y^2\right)=4^2-\left(x-y\right)^2=\left(4-x+y\right)\left(4+x-y\right)\)
d. \(\left(x-1\right)^2-4\left(2x-3\right)^2=\left(5-3x\right)\left(5x-7\right)\)
e. \(x^3-3x^2+3x-1=\left(x-1\right)^3\)
f. \(x^2-7=\left(x-\sqrt{7}\right)\left(x+\sqrt{7}\right)\)
c: Ta có: \(16-x^2+2xy-y^2\)
\(=16-\left(x-y\right)^2\)
\(=\left(4-x+y\right)\left(4+x-y\right)\)
d: Ta có: \(\left(x-1\right)^2-4\left(2x-3\right)^2\)
\(=\left(x-1\right)^2-\left(4x-6\right)^2\)
\(=\left(x-1-4x+6\right)\left(x-1+4x-6\right)\)
\(=\left(-3x+5\right)\left(5x-7\right)\)
e: \(x^3-3x^2+3x-1=\left(x-1\right)^3\)
f: \(x^2-7=\left(x-\sqrt{7}\right)\left(x+\sqrt{7}\right)\)
