a) Ta có : 6x2 - 13x + 6 = 6x2 - 9x - 4x + 6 = 3x(2x - 3) - 2(2x - 3) = (3x - 2)(2x - 3)
b) Ta có: 6x2 + 7x - 3 = 6x2 + 9x - 2x - 3 = 3x(2x + 3) - (2x + 3) = (3x - 1)(2x + 3)
\(a,6x^2-13x+6\)
\(=6x^2-9x-4x+6\)
\(=3x\cdot\left(2x-3\right)-x\cdot\left(2x-3\right)\)
\(=\left(2x-3\right)\cdot\left(3x-x\right)\)
\(=\left(2x-3\right)\cdot2x\)
\(b,6x^2+7x-3\)
\(=6x^2-2x+9x-3\)
\(=2x\cdot\left(3x-1\right)+3\cdot\left(3x-1\right)\)
\(=\left(3x-1\right)\cdot\left(2x+3\right)\)
\(a,6x^2-13x+6=6x^2-9x-4x+6\)
\(=3x\left(2x-3\right)-2\left(2x-3\right)=\left(2x-3\right)\left(3x-2\right)\)
\(b,6x^2+7x-3=6x^2-2x+9x-3\)
\(=2x\left(3x-1\right)+3\left(3x-1\right)=\left(3x-1\right)\left(2x+3\right)\)
