Question

phân tích đa thức thành nhân tử :

 

Answer 1

\(5,\left(2x-3y\right)^2-25y^2\\ =\left(2x-3y+5y\right)\left(2x-3y-5y\right)\\ =\left(2x+2y\right)\left(2x-8y\right)\\ =4\left(x+y\right)\left(x-4y\right)\\ 6,x^2-5xy+2x-10y\\ =x\left(x-5y\right)+2\left(x-5y\right)\\ =\left(x+2\right)\left(x-5y\right)\\ 7,x^3-5x^2-x+5\\ =x^2\left(x-5\right)-\left(x-5\right)\\ =\left(x-5\right)\left(x-1\right)\left(x+1\right)\\ 8,16-x^2+2x-1\\ =16-\left(x-1\right)^2\\ =\left(x+15\right)\left(17-x\right)\\ 9,3x+3y-x^2-2xy-y^2\\ =3\left(x+y\right)-\left(x+y\right)^2\\ =\left(x+y\right)\left(3-x-y\right)\)

Answer 2

8: =16-(x^2-2x+1)

=16-(x-1)^2

=(4-x+1)(4+x-1)

=(3+x)(5-x)

9: =3(x+y)-(x^2+2xy+y^2)

=3(x+y)-(x+y)^2

=(x+y)(3-x-y)

7: =x^2(x-5)-(x-5)

=(x-5)(x^2-1)

=(x-5)(x-1)(x+1)

6: =x(x-5y)+2(x-5y)

=(x-5y)(x+2)

5: =(2x-3y-5y)(2x-3y+5y)

=(2x-8y)(2x+2y)

=4(x-4y)(x+y)