Question

phân tích đa thức thành nhân tử x^2(x-3)^2- (x-3)^2- x^2+1 mn giúp em với

Answer 1

\(x^2\left(x-3\right)^2-\left(x-3\right)^2-x^2+1=\left(x-3\right)^2\left(x^2-1\right)-\left(x^2-1\right)=\left(x^2-1\right)\left[\left(x-3\right)^2-1\right]=\left(x-1\right)\left(x+1\right)\left(x-4\right)\left(x-2\right)\)

Answer 2

\(x^2\left(x-3\right)^2-\left(x-3\right)^2-x^2+1\)

\(=\left(x-3\right)^2\cdot\left(x-1\right)\left(x+1\right)-\left(x-1\right)\left(x+1\right)\)

\(=\left(x-1\right)\cdot\left(x+1\right)\left(x-2\right)\left(x-4\right)\)