\(x^3-5x+4\)
\(=x^3-x-4x+4\)
\(=x\left(x-1\right)\left(x+1\right)-4\left(x-1\right)\)
\(=\left(x-1\right)\left(x^2+x-4\right)\)
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` x^3 - 5x + 4 `
` = x^3 - x - 4x + 4 `
` = x ( x^2 - 1) - 4 ( x-1) `
` = x ( x-1) ( x+1) - 4 ( x -1 ) `
` = ( x -1) [ x(x+1) - 4] `
` = ( x -1 ) ( x^2 + x - 4 ) `
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