\(=\left(2+3+\dfrac{1}{4}+\dfrac{3}{4}\right)-\left(\dfrac{8}{17}+\dfrac{9}{17}\right)+2+\dfrac{1}{2022}\)
\(=6-1+2+\dfrac{1}{2022}\)
\(=7+\dfrac{1}{2022}=\dfrac{14155}{2022}\)
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