a,b,c,d:
e: TA có: \(\hat{AOB}+\hat{BOC}+\hat{A^{\prime}OC}=180^0\)
=>\(\hat{A^{\prime}OC}=180^0-60^0-60^0=60^0\)
5 cặp góc đối đỉnh là: \(\hat{AOB};\hat{A^{\prime}OB^{\prime}}\) ; \(\hat{A^{\prime}OB};\hat{AOB^{\prime}}\) ; \(\hat{COB};\hat{C^{\prime}OB^{\prime}}\) ; \(\hat{COB^{\prime}};\hat{BOC^{\prime}}\) ; \(\hat{AOC};\hat{A^{\prime}OC^{\prime}}\)
f: 5 cặp góc bằng nhau mà không đối đỉnh là: \(\hat{AOB};\hat{BOC}\) ; \(\hat{BOC};\hat{A^{\prime}OC}\) ; \(\hat{A^{\prime}OC};\hat{AOB}\) ; \(\hat{A^{\prime}OC};\hat{A^{\prime}OB^{\prime}}\) ; \(\hat{A^{\prime}OB^{\prime}};\hat{B^{\prime}OC^{\prime}}\)








