Question

\(\left\{{}\begin{matrix}\sqrt{3}x-\sqrt{2}y=1\\\sqrt{2}x+3\sqrt{3}y=4\sqrt{6}\end{matrix}\right.\)

Answer 1

\(\left\{{}\begin{matrix}\sqrt{3}x-\sqrt{2}y=1\\\sqrt{2}x+3\sqrt{3}y=4\sqrt{6}\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}\sqrt{6}x-2y=\sqrt{2}\\\sqrt{6}x+9y=12\sqrt{2}\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}-11y=-11\sqrt{2}\\\sqrt{3}x-\sqrt{2}y=1\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}y=\sqrt{2}\\x\sqrt{3}=1+y\sqrt{2}=3\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}y=\sqrt{2}\\x=\sqrt{3}\end{matrix}\right.\)