Question

\(\left\{{}\begin{matrix}\dfrac{x+1}{x-1}=\dfrac{y+3}{y+1}\\3x+2y+2=0\end{matrix}\right.\)

Answer 1

ĐKXĐ: \(x\ne1;y\ne-1\)

\(\left\{{}\begin{matrix}\dfrac{x+1}{x-1}=\dfrac{y+3}{y+1}\\3x+2y+2=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}\left(x+1\right)\left(y+1\right)=\left(x-1\right)\left(y+3\right)\\3x+2y=-2\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}-2x+2y=-4\\3x+2y=-2\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{2}{5}\\y=-\dfrac{8}{5}\end{matrix}\right.\)