ĐKXĐ: x<>2 và y<>0
\(\left\{{}\begin{matrix}\dfrac{2}{\left|x-2\right|}+\dfrac{1}{y}=2\\\dfrac{6}{\left|x-2\right|}-\dfrac{2}{y}=1\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{4}{\left|x-2\right|}+\dfrac{2}{y}=4\\\dfrac{6}{\left|x-2\right|}-\dfrac{2}{y}=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{10}{\left|x-2\right|}=5\\\dfrac{2}{\left|x-2\right|}+\dfrac{1}{y}=2\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\left|x-2\right|=2\\\dfrac{1}{y}=2-\dfrac{2}{2}=2-1=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x-2\in\left\{2;-2\right\}\\y=1\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x\in\left\{4;0\right\}\\y=1\end{matrix}\right.\)
