Question

\(\left\{{}\begin{matrix}2x-\dfrac{1}{y}=5\\x+\dfrac{3}{y}=6\end{matrix}\right.\)

Giải hpt

Answer 1

ĐKXĐ: y<>0

\(\left\{{}\begin{matrix}2x-\dfrac{1}{y}=5\\x+\dfrac{3}{y}=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}6x-\dfrac{3}{y}=15\\x+\dfrac{3}{y}=6\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}7x=21\\x+\dfrac{3}{y}=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\\dfrac{3}{y}=6-x=6-3=3\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x=3\\y=1\left(nhận\right)\end{matrix}\right.\)