Question

\(\left(2x-3\right)^2=16\)

Answer 1

`->` \(\left[{}\begin{matrix}2x-3=4\\2x-3=-4\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)

Answer 2

=>2x-3=4 hoặc 2x-3=-4

=>2x=7 hoặc 2x=-1

=>x=7/2 hoặc x=-1/2

Answer 3

`(2x-3)^2 = 16`

`=>` \(\left[{}\begin{matrix}\left(2x-3\right)^2=4^2\\\left(2x-3\right)^2=\left(-4\right)^2\end{matrix}\right.\)

`<=>` \(\left[{}\begin{matrix}2x-3=4\\2x-3=-4\end{matrix}\right.\)

`<=>` \(\left[{}\begin{matrix}2x=7\\2x=-1\end{matrix}\right.\)

`<=>` \(\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)

Answer 4