=>2,2-0,3x=2,6+0,4x-4
=>-0,7x=-0,8
hay x=8/7
\(\Leftrightarrow2,2-0,3x=-\dfrac{7}{5}+0,4x\Leftrightarrow-\dfrac{7}{10}x=-\dfrac{18}{5}\Leftrightarrow x=\dfrac{36}{7}\)
=>2,2-0,3x=2,6+0,4x-4
=>-0,7x=-0,8
hay x=8/7
\(\Leftrightarrow2,2-0,3x=-\dfrac{7}{5}+0,4x\Leftrightarrow-\dfrac{7}{10}x=-\dfrac{18}{5}\Leftrightarrow x=\dfrac{36}{7}\)
Giải PT sau:
\(3.\left(2,2-0,3x\right)=2,6+\left(0,1x-4\right)\)
Giair pt
a)3+2,25x+2,6=2x+5+0,4x
b)5x+3,48-2,35x=5,38-2,9x+10,42
c)3(2,2-0,3x)=2,6+(0,1x-4)
d)3,6-0,5(2x+1)=x-0,25(2-4x)
Giải các phương trình sau:
a. 3(2,2−0,3x)=2,6+(0,1x−4)3(2,2−0,3x)=2,6+(0,1x−4)
b. 3,6−0,5(2x+1)=x−0,25(2−4x)
Giải các phương trình sau: 3(2,2 – 0,3x) = 2,6 + (0,1x – 4)
Giúp mình với ạ:
1) (0,4x-2) - (1,5x+1)- (-4x-0,8)=3,6
2) \(\left(\frac{3}{4}x+3\right)-\left(\frac{2}{3}x-4\right)-\left(\frac{1}{6}x+1\right)=\left(\frac{1}{3}x+4\right)-\left(\frac{1}{3}x-3\right)\)
3) x+2x+3x+4x+...+100x=-21
Tính
\(\left(0,3x^3y-\frac{16}{3}z\right)^2\)
b) \(\left[\left(2u+5\right)-3z\right]^2\)
Tìm x,y:
1..\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
2. \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
3. \(\left|4.x\right|-\left|-13.5\right|=\left|2\frac{1}{4}\right|\)
4. \(\frac{-2,6}{x}=\frac{-12}{42}\)
5. \(\left|x+5\right|+\left(3y-4\right)^{2012}=0\)
Giải phương trình:
a) 1,2-(x-0,8)= -2(0,9+x)
b) 2,3x-2(0,7+2x)=3,6-1,7x
c) 3(2,2-0,3x)=2,6+(0,1x-4)
d) 3,6-0,5(2x+1)=x-0,25(2-4x)
BT7: Tính
\(3,C=\left(5-1\right)\left(5+1\right)\left(5^2+1\right)\left(5^4+1\right)...\left(5^{16}+1\right)\)
\(4,D=15\left(4^2+1\right)\left(4^4+1\right)...\left(4^{64}+1\right)\)
\(5,E=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)...\left(5^{128}+1\right)+\left(5^{256}-1\right)\)