a: 5x+20=0
=>5x=-20
=>x=-4
b: \(\dfrac{2x+3}{3}+\dfrac{1}{2}=\dfrac{x+1}{4}\)
=>\(\dfrac{4\left(2x+3\right)+6}{12}=\dfrac{3\left(x+1\right)}{12}\)
=>4(2x+3)+6=3x+3
=>8x+12+6=3x+3
=>8x+18=3x+3
=>5x=-15
=>x=-3
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