Question

help

Answer 1

\(a,4x^2-25=0\\ \Rightarrow\left(2x-5\right)\left(2x+5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{5}{2}\end{matrix}\right.\\ b,\dfrac{x-3}{5}-\dfrac{x}{2}=\dfrac{3-x}{10}\\ \Rightarrow\dfrac{2\left(x-3\right)-5x}{10}=\dfrac{3-x}{10}\\ \Rightarrow2x-6-5x=3-x\\ \Rightarrow2x-6-5x-3+x=0\\ \Rightarrow-2x-9=0\\ \Rightarrow-2x=9\\ \Rightarrow x=-\dfrac{9}{2}\)