Question

help me: phân tích đa thức thành nhân tử

Answer 1

a) \(\dfrac{2x-4}{x^2-1}.\dfrac{x^3-3x^2+3x-1}{x-2}\left(x\ne-1;1;2\right)\)

\(=\dfrac{2\left(x-2\right)}{\left(x-1\right)\left(x+1\right)}.\dfrac{\left(x-1\right)^3}{x-2}=\dfrac{2\left(x-1\right)^2}{x+1}\)

b) \(\dfrac{x^2-3x+2}{x^2-5x+6}.\dfrac{x^2-x-6}{x^2-2x+1}\left(x\ne1;2;3\right)\)

\(=\dfrac{\left(x-1\right)\left(x-2\right)}{\left(x-2\right)\left(x-3\right)}.\dfrac{\left(x-3\right)\left(x+2\right)}{\left(x-1\right)^2}=\dfrac{x+2}{x-1}\)