ĐK x >= 3/2
pt <=> \(\sqrt{2x-3}=x-3\)
ĐK x >= 3
<=> 2x - 3 = \(x^2-6x+9\)
=> \(x^2-8x+12=0\)
=> \(\left(x-2\right)\left(x-6\right)=0\)
=> x = 2 ( loại x > 3 ) và x = 6 ( TM)
Vậy x = 6
Gpt: \(\sqrt{x+5}+\sqrt{3-x}-2\left(\sqrt{15-2x-x^2}+1\right)=0\)
GPT :
\(3\sqrt{x^3+8}=2x^2-3x+10\)
GPT:\(\sqrt{\dfrac{x+1}{2x}}+\sqrt{\dfrac{2x}{x+3}}=2\)
gpt:
\(\sqrt{2x^2-1}+\sqrt{x^2-3x-2}=\sqrt{2x^2+2x+3}+\sqrt{x^2-x+2}\)
GPT :
\(x^3-4x^2+5x-1-\sqrt{2x-3}=0\)
GPT
\(\sqrt[]{2x+3+\sqrt{x+2}}+\sqrt[]{2x+2-\sqrt{2+x}}=1+2\sqrt{x+2}\)
GPT :
\(x^2+\sqrt[3]{x^4-x^2}=2x+1\)
GPT :
\(x^2+\sqrt[3]{x^4-x^2}=2x+1\)
GPT :
\(\sqrt[4]{2x^3+x^2-2x+8}+\sqrt[4]{3x^3+x^2-2x+10}=2\sqrt[4]{x^2-2x+4}\)
GPT
:\(x+4\sqrt{x+3}+2\sqrt{3-2x}=11\)
