Question

Giúp với ạ

Answer 1

\(n_{CuSO_4}=n_{CuSO_4.5H_2O}=\dfrac{50}{250}=0,2\left(mol\right)\\ \rightarrow m_{CuSO_4}=0,2.160=32\left(g\right)\\ \rightarrow m_{dm}=m_{dd}-m_{ct}=200-32=168\left(g\right)\)

Answer 2

\(n_{CuSO_4.5H_2O}=\dfrac{50}{250}=0,2\left(mol\right)\)

=> \(n_{CuSO_4}=0,2\left(mol\right)\Rightarrow m_{CuSO_4}=0,2.160=32\left(g\right)\)

m_dm =  200 - 32 =168 (g)