\(=\dfrac{x+3\sqrt{x}+x-3\sqrt{x}}{x-9}:\dfrac{\sqrt{x}+3-3}{\sqrt{x}+3}\)
\(=\dfrac{2x}{x-9}\cdot\dfrac{\sqrt{x}+3}{\sqrt{x}}=2\sqrt{x}\left(\sqrt{x}-3\right)\)
Đúng 0
Bình luận (0)