Question

Giúp mk với

Answer 1

ĐKXĐ:\(x\ne1\)

\(\sqrt{\dfrac{2x-3}{x-1}}=2\\ \Leftrightarrow\dfrac{2x-3}{x-1}=4\\ \Leftrightarrow2x-3=4x-4\\ \Leftrightarrow4x-4-2x+3=0\\ \Leftrightarrow2x-1=0\\ \Leftrightarrow x=\dfrac{1}{2}\)