\(B=\dfrac{3x^2+3x-2x^2+2x-x+3}{\left(x-1\right)\left(x+1\right)}=\dfrac{x^2+4x+3}{\left(x-1\right)\left(x+1\right)}=\dfrac{x+3}{x-1}\)
\(P=A\cdot B=\dfrac{x^2}{x+3}\cdot\dfrac{x+3}{x-1}=\dfrac{x^2}{x-1}\)
a: |P|=-P
=>P<=0
=>x^2/x-1<=0
=>x-1<0
=>x<1
b: |P|>-P
=>P>=0
=>x-1>0
=>x>1
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giúp mk vs ạ ai nhanh mk tick nha 
