Question

giúp mình vs

Answer 1

\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{3}x+\dfrac{1}{3}-\dfrac{1}{4}y-\dfrac{1}{2}=\dfrac{2}{5}x-\dfrac{8}{5}\\\dfrac{1}{4}x-\dfrac{3}{4}-\dfrac{1}{3}y+1-2y+x=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}-\dfrac{1}{15}x-\dfrac{1}{4}y=-\dfrac{43}{30}\\\dfrac{5}{4}x-\dfrac{7}{3}y=-\dfrac{1}{4}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}4x+15y=86\\15x-28y=-3\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}60x+225y=1290\\60x-112y=-12\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=\dfrac{1302}{337}\\x=\dfrac{2363}{337}\end{matrix}\right.\)