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Bài 10:
1: \(x-\frac27=\frac43\)
=>\(x=\frac43+\frac27=\frac{28+6}{21}=\frac{34}{21}\)
2: \(x+\frac34=\frac68\)
=>\(x+\frac34=\frac34\)
=>x=0
3: \(\left|x\right|-\frac34=\frac23+\frac14\)
=>\(\left|x\right|=\frac23+\frac44=\frac23+1=\frac53\)
=>\(\left[\begin{array}{l}x=\frac53\\ x=-\frac53\end{array}\right.\)
4: \(\frac{x+1}{5}=\frac43\)
=>\(x+1=\frac43\cdot5=\frac{20}{3}\)
=>\(x=\frac{20}{3}-1=\frac{17}{3}\)
5: \(\frac{3x}{2}+\frac{3x}{4}=\frac56\)
=>\(\frac{6x}{4}+\frac{3x}{4}=\frac56\)
=>\(x\cdot\frac94=\frac56\)
=>\(x=\frac56:\frac94=\frac56\cdot\frac49=\frac{20}{54}=\frac{10}{27}\)
Bài 9:
c: \(-\frac34x+\frac16x=1-2\frac59\)
=>\(x\left(-\frac34+\frac16\right)=1-2-\frac59=-1-\frac59=-\frac{14}{9}\)
=>\(x\cdot\left(-\frac{9}{12}+\frac{2}{12}\right)=-\frac{14}{9}\)
=>\(x\cdot\frac{-7}{12}=\frac{-14}{9}\)
=>\(x=\frac{14}{9}:\frac{7}{12}=\frac{14}{9}\cdot\frac{12}{7}=2\cdot\frac43=\frac83\)
d: \(\left|2x-\frac38\right|+2\frac34=3\frac{1}{16}\)
=>\(\left|2x-\frac38\right|=3+\frac{1}{16}-2-\frac34=1+\frac{1}{16}-\frac34=\frac14+\frac{1}{16}=\frac{5}{16}\)
=>\(\left[\begin{array}{l}2x-\frac38=\frac{5}{16}\\ 2x-\frac38=-\frac{5}{16}\end{array}\right.\Rightarrow\left[\begin{array}{l}2x=\frac{5}{16}+\frac38=\frac{11}{16}\\ 2x=-\frac{5}{16}+\frac38=\frac{1}{16}\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac{11}{32}\\ x=\frac{1}{32}\end{array}\right.\)
a: \(x-\frac{17}{36}=-\frac{15}{16}\cdot\frac{4}{27}\)
=>\(x-\frac{17}{36}=-\frac{4}{16}\cdot\frac{15}{27}=-\frac14\cdot\frac59=-\frac{5}{36}\)
=>\(x=-\frac{5}{36}+\frac{17}{36}=\frac{12}{36}=\frac13\)
b: \(\left|x-\frac16\right|-\frac{6}{16}=25\%\)
=>\(\left|x-\frac16\right|=\frac{4}{16}+\frac{6}{16}=\frac{10}{16}=\frac58\)
=>\(\left[\begin{array}{l}x-\frac16=\frac58\\ x-\frac16=-\frac58\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac58+\frac16=\frac{15}{24}+\frac{4}{24}=\frac{19}{24}\\ x=-\frac58+\frac16=\frac{-15+4}{24}=-\frac{11}{24}\end{array}\right.\)
