h: \(\left(1+\dfrac{1}{3}-\dfrac{1}{4}\right)\cdot\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
\(=\dfrac{12+4-3}{12}\cdot\left(\dfrac{16-15}{20}\right)^2\)
\(=\dfrac{5}{4}\cdot\dfrac{1}{20^2}=\dfrac{5}{1600}=\dfrac{1}{320}\)
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