Question

giúp mình với ạ

Answer 1

\(a,=x\left(x-y\right)+\left(x-y\right)=\left(x+1\right)\left(x-y\right)\\ b,=\left(x^2-1\right)\left(x-1\right)=\left(x-1\right)^2\left(x+1\right)\\ c,=\left(x^2-9\right)\left(1-x^2\right)=\left(x-3\right)\left(x+3\right)\left(1-x\right)\left(1+x\right)\\ d,=\left(x+2\right)^2-y^2=\left(x+y+2\right)\left(x-y+2\right)\\ e,=\left(x^2-4\right)\left(x+y\right)=\left(x-2\right)\left(x+2\right)\left(x+y\right)\\ f,=\left(x+4\right)\left(3-x\right)\\ g,=5\left(x-y\right)\left(x+y\right)-10\left(x-y\right)=\left(5x+5y-10\right)\left(x-y\right)\\ h,=\left(2x-5\right)\left(2x+5\right)\\ i,=3\left[\left(x-y\right)^2-4z^2\right]=3\left(x-y-2z\right)\left(x-y+2z\right)\\ j,=\left(2x-3\right)^2\\ k,=-\left[\left(2x-3y\right)^2-25\right]=-\left(2x-3y-5\right)\left(2x-3y+5\right)\\ l,=x^2+2x+4x+8=\left(x+2\right)\left(x+4\right)\)

\(m,=x^2+7x-x-7=\left(x+7\right)\left(x-1\right)\\ n,=2x^2+5x-2x-5=\left(2x+5\right)\left(x-1\right)\\ o,=5\left(x-4y\right)\\ p,=\left(x+1\right)\left(1+x+1\right)=\left(x+1\right)\left(x+2\right)\\ q,=2x\left(x-1\right)\)