\(A=\dfrac{5}{\sqrt{x}+1}\left(đk:x\ge0\right)\)
Vì x≥0 => A≤\(\dfrac{5}{2}\)
\(MaxA=\dfrac{5}{2}\Leftrightarrow x=0\)
\(B=\dfrac{15}{3\sqrt{x}+1}\left(đk:x\ge0\right)\)
Vì x≥0 => \(B\le\dfrac{15}{1}=15\)
\(MaxB=15\Leftrightarrow x=0\)
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