Bài 1:
a: \(\Leftrightarrow\left(3x+2\right)^2-6\left(3x-2\right)=9x^2\)
\(\Leftrightarrow9x^2+12x+4-18x+12=9x^2\)
=>-6x+16=0
=>-6x=-16
=>x=8/3
b: \(\Leftrightarrow3\left(3-x\right)+2\left(5x-1\right)=4\)
=>9-3x+10x-2=4
=>7x+7=4
=>7x=-3
=>x=-3/7
c: \(\Leftrightarrow-3\left(4x+1\right)=2\left(4x-1\right)-6x-8\)
=>\(-12x-3=8x-2-6x-8=2x-10\)
=>-14x=-7
=>x=1/2
d: \(\Leftrightarrow\dfrac{5-x}{4x\left(x-2\right)}+\dfrac{7}{8x}=\dfrac{x-1}{2x\left(x-2\right)}+\dfrac{1}{8\left(x-2\right)}\)
\(\Leftrightarrow2\left(5-x\right)+7\left(x-2\right)=4\left(x-1\right)+x\)
=>\(10-2x+7x-14=4x-4+x=5x-4\)
=>5x-4=5x-4(luôn đúng)
=>S=R\{0;2}
e: \(\Leftrightarrow x^3+1-x^3+1=\dfrac{3}{x}\)
=>\(2x=3\)
=>x=3/2
