Question

Giup mik gấp bài này vs.plsss

Answer 1

Ta có: \(\frac{731}{217}=\frac{651+80}{217}=3+\frac{80}{217}\)

\(\frac{221}{71}=\frac{213+8}{71}=3+\frac{8}{71}=3+\frac{80}{710}\)

mà \(\frac{80}{217}>\frac{80}{710}\left(217<710\right)\)

nên \(\frac{731}{217}>\frac{221}{71}>3\)

=>\(5>\frac{731}{217}>\frac{221}{71}\) (1)

Ta có: \(\frac{1711}{341}=\frac{1705+6}{341}=5+\frac{6}{341}\)

\(\frac{721}{143}=\frac{715+6}{143}=5+\frac{6}{143}\)

mà \(\frac{6}{341}<\frac{6}{143}\left(341>143\right)\)

nên \(5<\frac{1711}{341}<\frac{721}{143}\) (2)

Từ (1),(2) suy ra \(\frac{221}{71}<\frac{731}{217}<\frac{1711}{341}<\frac{721}{143}\)

Answer 2

Ta có: \(\frac{731}{217}=\frac{651+80}{217}=3+\frac{80}{217}\)

\(\frac{221}{71}=\frac{213+8}{71}=3+\frac{8}{71}=3+\frac{80}{710}\)

mà \(\frac{80}{217}>\frac{80}{710}\left(217<710\right)\)

nên \(\frac{731}{217}>\frac{221}{71}>3\)

=>\(5>\frac{731}{217}>\frac{221}{71}\) (1)

Ta có: \(\frac{1711}{341}=\frac{1705+6}{341}=5+\frac{6}{341}\)

\(\frac{721}{143}=\frac{715+6}{143}=5+\frac{6}{143}\)

mà \(\frac{6}{341}<\frac{6}{143}\left(341>143\right)\)

nên \(5<\frac{1711}{341}<\frac{721}{143}\) (2)

Từ (1),(2) suy ra \(\frac{221}{71}<\frac{731}{217}<\frac{1711}{341}<\frac{721}{143}\)