Question

giúp mik bài này với ạ

 

Answer 1

\(\dfrac{x-2}{2x+1}=\dfrac{2}{3}\left(ĐK:x\ne-\dfrac{1}{2}\right)\\ \left(x-2\right)3=\left(2x+1\right)2\\ 3x-6=4x+2\\ -6-2=4x-3x\\ 4x-3x=-6-2\\ 1x=-8\\ x=-8:1\\ x=-8\)