Bài 1:
a: Ta có: \(\left|2x-\dfrac{1}{3}\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-\dfrac{1}{3}=-4\\2x-\dfrac{1}{3}=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=-\dfrac{11}{3}\\2x=\dfrac{13}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{11}{6}\\x=\dfrac{13}{6}\end{matrix}\right.\)