\(\dfrac{1}{8}+\dfrac{2}{3}+\dfrac{7}{16}\)
= \(\dfrac{2}{16}+\dfrac{7}{16}+\dfrac{2}{3}\)
= \(\dfrac{9}{16}+\dfrac{2}{3}\)
= \(\dfrac{59}{48}\)
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\(\dfrac{1}{8}+\dfrac{2}{3}+\dfrac{7}{16}=\dfrac{6}{48}+\dfrac{32}{48}+\dfrac{21}{48}=\dfrac{59}{48}\)
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