Question

giúp em với e cần gấp ạ

 

Answer 1

\(a,ĐK:x\ge0\\ PT\Leftrightarrow\sqrt{x}=2-\sqrt{3}+1=3-\sqrt{3}\\ \Leftrightarrow x=\left(3-\sqrt{3}\right)^2=12-6\sqrt{3}\\ b,ĐK:x\ge2\\ PT\Leftrightarrow2\sqrt{x-2}-\sqrt{x-2}-3\sqrt{x-2}=-1\\ \Leftrightarrow-2\sqrt{x-2}=-1\Leftrightarrow x-2=\dfrac{1}{4}\Leftrightarrow x=\dfrac{9}{4}\left(tm\right)\)