a: \(A=\dfrac{1+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-1\right)}\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}+1}\)
\(=\dfrac{\sqrt{x}-1}{\sqrt{x}}\)
b: A=1/3
=>\(\dfrac{\sqrt{x}-1}{\sqrt{x}}=\dfrac{1}{3}\)
=>3*căn x-3=căn x
=>2*căn x=3
=>căn x=3/2
=>x=9/4
Đúng 0
Bình luận (1)









giúp e vs ạ :<