Question

giúp e vs ạ

Answer 1

a: \(P=\dfrac{\sqrt{a}+1-\sqrt{a}+1+a-1}{a-1}=\dfrac{a+1}{a-1}\)

b: \(=\dfrac{\sqrt{x}+1+2\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+1\right)}\cdot\dfrac{x-1}{3\sqrt{x}+1}\)

\(=\dfrac{\sqrt{x}-1}{\sqrt{x}}\)

c: \(=\dfrac{3\sqrt{x}+3-2\sqrt{x}+4}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}\cdot\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)}{\sqrt{x}+7}\)

\(=\dfrac{\sqrt{x}}{\sqrt{x}-2}\)

d: \(P=\dfrac{\sqrt{x}+2+\sqrt{x}-1}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}\cdot\dfrac{x-\sqrt{x}}{2\sqrt{x}+1}=\dfrac{x-\sqrt{x}}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}\)

\(=\dfrac{\sqrt{x}}{\sqrt{x}+2}\)