Question

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Answer 1

 

3: \(C=\left(\sqrt{\dfrac{16}{9}}+1\right)^2-\left(\sqrt{\dfrac{25}{16}}-\dfrac{1}{4}\right)^{100}+\dfrac{1}{3}:\dfrac{3}{5}\)

\(=\left(\dfrac{4}{3}+1\right)^2-\left(\dfrac{5}{4}-\dfrac{1}{4}\right)^{100}+\dfrac{1}{3}\cdot\dfrac{5}{3}\)

\(=\dfrac{49}{9}-1+\dfrac{5}{9}=\dfrac{54}{9}-1=6-1=5\)

Bài 2:

1: \(A=\left(-2\dfrac{1}{5}+\dfrac{2}{7}-\dfrac{12}{13}\right)-\left(-\dfrac{5}{7}+\dfrac{1}{13}\right)\)

\(=-2-\dfrac{1}{5}+\dfrac{2}{7}-\dfrac{12}{13}+\dfrac{5}{7}-\dfrac{1}{13}\)

\(=-\dfrac{11}{5}+\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(-\dfrac{12}{13}-\dfrac{1}{13}\right)\)

\(=-\dfrac{11}{5}\)

2: Sửa đề: \(B=\dfrac{12}{17}\cdot\dfrac{5}{7}-\dfrac{-12}{17}\cdot\dfrac{1}{7}+12\cdot\dfrac{1}{17\cdot7}\)

\(=\dfrac{12}{17}\cdot\dfrac{5}{7}+\dfrac{12}{17}\cdot\dfrac{1}{7}+\dfrac{12}{17}\cdot\dfrac{1}{7}\)

\(=\dfrac{12}{17}\left(\dfrac{5}{7}+\dfrac{1}{7}+\dfrac{1}{7}\right)=\dfrac{12}{17}\)

3: \(C=\left(\dfrac{1}{3}-2\dfrac{1}{6}\right)^2:\left(-3\dfrac{13}{36}\right)\)

\(=\left(\dfrac{2}{6}-\dfrac{13}{6}\right)^2:\left(-3\dfrac{13}{36}\right)\)

\(=-\left(\dfrac{11}{6}\right)^2:\left(3+\dfrac{13}{36}\right)\)

\(=-\dfrac{121}{36}:\dfrac{121}{36}=-1\)