Question

giai ptr 

8\(\left(\dfrac{1}{x}+\dfrac{1}{y}\right)+\dfrac{10}{3}.\dfrac{2}{y}=1\)

Answer 1

=>\(\dfrac{8}{x}+\dfrac{8}{y}+\dfrac{20}{3}\cdot\dfrac{1}{y}=1\)

=>\(\dfrac{8}{x}+\dfrac{44}{3y}=1\)

=>\(\dfrac{24y+44x}{3xy}=1\)

=>44x+24y=3xy

=>44x+24y-3xy=0

=>44x-3y(x-8)=0

=>44x-352-3y(x-8)=352

=>(x-8)(44-3y)=352

=>\(\left(x-8;44-3y\right)\in\left\{\left(32;11\right)\left(44;8\right);\left(176;2\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(40;11\right);\left(52;12\right);\left(184;14\right)\right\}\)