Question

Giải PT:

\(\frac{201-x}{99}\) +  \(\frac{203-x}{97}\)=  \(\frac{205-x}{95}\)+  3  = 0

Answer 1

Đề bài tương đương:

\(\frac{201-x}{99}-1+\frac{203-x}{97}-1-\frac{205-x}{95}-1=0\)

\(\Leftrightarrow\frac{201-x}{99}-\frac{99}{99}+\frac{203-x}{97}-\frac{95}{97}-\frac{205-x}{95}-\frac{95}{95}=0\)

\(\Leftrightarrow\frac{300-x}{99}+\frac{300-x}{97}-\frac{300-x}{95}=0\)

\(\Leftrightarrow\left(300-x\right).\left(\frac{1}{99}+\frac{1}{97}-\frac{1}{95}\right)=0\)

\(\Leftrightarrow300-x=0\left(\frac{1}{99}+\frac{1}{97}-\frac{1}{95}\ne0\right)\)

\(\Leftrightarrow x=300\)