Question

\(\dfrac{201-x}{99}+\dfrac{203-x}{97}=\dfrac{205-x}{95}+3=0\)

Answer 1

`(201-x)/99+(203-x)/97+(205-x)/95+3=0`

`<=>(201-x)/99+1+(203-x)/97+1+(205-x)/95+1=0`

`<=>(300-x)/99+(300-x)/97+(300-x)/95=0`

`<=>(300-x)(1/99+1/97+1/95)=0`

`<=>300-x=0`

`<=>x=300`

Vậy `x=300`

Answer 2

Sai đề.

Answer 3

Vì 205-x/95+3=0

=>205-x/95=0-3=-3

=>205-x=-3*95=-285

=>x=205-(-285)=490

Vậy x=490