ĐKXĐ: \(x\ge4\)
\(\sqrt{3x+1}-\sqrt{x-4}+2x+5=0\)
\(\Leftrightarrow\dfrac{2x+5}{\sqrt{3x+1}+\sqrt{x-4}}+2x+5=0\)
\(\Leftrightarrow\left(2x+5\right)\left(\dfrac{1}{\sqrt{3x+1}+\sqrt{x-4}}+1\right)=0\)
\(\Leftrightarrow2x+5=0\) (do \(\dfrac{1}{\sqrt{3x+1}+\sqrt{x-4}}+1>0\))
\(\Leftrightarrow x=-\dfrac{5}{2}\) (ko thỏa mãn ĐKXĐ)
Vậy pt đã cho vô nghiệm