Question

Giải phương trình sau: x² - 10x = -25

Answer 1

=>x²-10x+25=0

=>(x-5)^2=0

=>x-5=0

=>x=5

Answer 2

\(x^2-10x=-25\)

--> \(x^2-10x+25=0\)

---> \(x^2-2\cdot x\cdot5+5^2=0\)

--> \(\left(x-5\right)^2=0\)

--> \(x-5=0->x=5\)

Answer 3

\(x^2-10x=-25\)

\(\Leftrightarrow x^2-10x+25=0\)

\(\Leftrightarrow\left(x-5\right)^2=0\Leftrightarrow x-5=0\Leftrightarrow x=5\)