`[158-x]/31+[185-x]/29+[208-x]/27+[227-x]/25=10`
`<=>[158-x]/31-1+[185-x]/29-2+[208-x]/27-3+[227-x]/25-4=0`
`<=>[127-x]/21+[127-x]/29+[127-x]/27+[127-x]/25=0`
`<=>(127-x)(1/21+1/29+1/27+1/25)=0`
`<=>127-x=0`
`<=>x=127`
`[158-x]/31+[185-x]/29+[208-x]/27+[227-x]/25=10`
`<=>[158-x]/31-1+[185-x]/29-2+[208-x]/27-3+[227-x]/25-4=0`
`<=>[127-x]/21+[127-x]/29+[127-x]/27+[127-x]/25=0`
`<=>(127-x)(1/21+1/29+1/27+1/25)=0`
`<=>127-x=0`
`<=>x=127`
giải pt sau :158-x/31 + 185-x/29 +208-x/27 + 277-x/25
GIẢI PHƯƠNG TRÌNH
1)\(\dfrac{x+1}{35}+\dfrac{x+3}{33}=\dfrac{x+5}{31}+\dfrac{x+7}{29}\)
2)x(x+1)(x+2)(x+3)=24
3)\(\dfrac{x-1}{13}-\dfrac{2x-13}{15}=\dfrac{3x-15}{27}-\dfrac{4x-27}{29}\)
4)\(\dfrac{1909-x}{91}+\dfrac{1907-x}{93}+\dfrac{1905-x}{95}+\dfrac{1903-x}{91}+4=0\)
giải phương trình sau:
\(\dfrac{x-5}{95}+\dfrac{x-132}{32}=\dfrac{x-132}{31}+\dfrac{x-10}{90}\)
Giải các phương trình:
\(\dfrac{x+24}{1996}+\dfrac{x+25}{1995}+\dfrac{x+26}{1994}+\dfrac{x+27}{1993}+\dfrac{x+2036}{4}=0\)
\(\dfrac{29-x}{21}\)+\(\dfrac{27-x}{23}\)+\(\dfrac{25-x}{25}\)+\(\dfrac{23-x}{27}\)=-4
Giải các phương trình sau: (TM ĐK)
1) \(\dfrac{11}{x}=\dfrac{9}{x+1}+\dfrac{2}{x-4}\)
2) \(\dfrac{14}{3x-12}-\dfrac{2+x}{x-4}=\dfrac{3}{8-2x}-\dfrac{5}{6}\)
3) \(\dfrac{x+5}{x^2-5x}-\dfrac{x+25}{2x^2-50}=\dfrac{x-5}{2x^2+10}\)
4) \(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{16}{x^2-1}\)
5) \(\left(1-\dfrac{x-1}{x+1}\right)\left(x+2\right)=\dfrac{x+1}{x-1}+\dfrac{x-1}{x+1}\)
mng giúp mk bài này nha. Cảm ơn bạn nhiều
giải phương trình sau:
\(\dfrac{x+25}{75}+\dfrac{x+30}{70}=\dfrac{x+35}{65}+\dfrac{x+40}{60}\)
mọi người ơi giúp mình câu giải phương trình này với:
\(\dfrac{x-5}{1990}+\dfrac{x-15}{1980}+\dfrac{x-25}{1970}+\dfrac{x-1990}{5}+\dfrac{x-1980}{15}+\dfrac{x-1970}{25}=0\)
giải phương trình :
\(\dfrac{80}{x+4}\)+ \(\dfrac{80}{x-4}\) = \(\dfrac{25}{3}\)