Question

Giải dùm tui từ câu 36-40 với ạ

Answer 1

39:

\(y'=\dfrac{\left(2x-1\right)'\left(x+1\right)-\left(2x-1\right)\left(x+1\right)'}{\left(x+1\right)^2}=\dfrac{2\left(x+1\right)-2x+1}{\left(x+1\right)^2}=\dfrac{3}{\left(x+1\right)^2}\)

Khi x=-2 thì y'=3/(-2+1)^2=3

y=2*(-2)-1/(-2+1)=-5/-1=5

y-f(-2)=f'(-2)(x+2)

=>y-5=3(x+2)=3x+6

=>y=3x+11