Giải
\(đk:6x-2\ne0=>x\ne\dfrac{1}{3}\\\dfrac{x+2}{6x-2}=\dfrac{1}{4}\\ =>\dfrac{4\left(x+2\right)}{4\left(6x-2\right)}=\dfrac{6x-2}{4\left(6x-2\right)}\\ =>4\left(x+2\right)=6x-2\\ =>4x+8-6x+2=0\\ =>-2x+10=0\\ =>-2x=-10\\ =>x=\left(-10\right):\left(-2\right)\\ =>x=5\left(thoamanđk\right)\)
Vậy \(x=5\)