Bài 2:
3: Ta có: \(\sqrt{36}\cdot\sqrt{\dfrac{25}{16}}+\dfrac{1}{4}\)
\(=6\cdot\dfrac{5}{4}+\dfrac{1}{4}\)
\(=\dfrac{15}{2}+\dfrac{1}{4}=\dfrac{31}{4}\)
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