tìm x \(\in\) Q biết rằng
\(\dfrac{11}{12}\) - ( \(\dfrac{2}{5}\) + x ) = \(\dfrac{2}{3}\)
2x \(\times\) ( x - \(\dfrac{1}{7}\) ) = 0
\(\dfrac{3}{4}\) + \(\dfrac{1}{4}\) : x = \(\dfrac{2}{5}\)
e)\(\dfrac{2-x}{4}=\dfrac{3x-1}{-3}\)\(\) f)\(\dfrac{x}{7}=\dfrac{x+16}{35}\)
Tìm x: \(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{8}-\dfrac{1}{16} +...-\dfrac{1}{1024}=\dfrac{x}{1024}\)
\((\dfrac{3}{4}x -\dfrac{9}{16}) (\dfrac{1}{3} + \dfrac{-3}{5} : x ) =0\)
Tìm \(x\)
a) \(\dfrac{2-x}{4}=\dfrac{3x-1}{3}\)
b) \(\dfrac{x}{7}=\dfrac{x+16}{35}\)
c) \(\sqrt{x^2+1}=3\)
a,2.(\(\dfrac{1}{4}\)+x)\(^3\)=(\(-\dfrac{27}{4}\))
b,(x+\(\dfrac{1}{2}\))\(^3\):3=\(\dfrac{-1}{81}\)
c,(\(\dfrac{2}{3}\)-x)\(^2\)=1:\(\dfrac{4}{9}\)
d,(2x-\(\dfrac{1}{5}\))\(^2\)+\(\dfrac{16}{25}\)=1
e,(\(\dfrac{2}{5}\)-3x)\(^2\)-\(\dfrac{1}{5}\)=\(\dfrac{4}{25}\)
\(\dfrac{-16}{x+1}=\dfrac{x+1}{-4}\)
1,\(\dfrac{3}{16}\)- ( x - \(\dfrac{5}{4}\) ) - ( \(\dfrac{3}{4}\) + \(\dfrac{-7}{8}\) - 1 ) = \(2\dfrac{1}{2}\)
2,\(\dfrac{1}{2}\) . ( \(\dfrac{1}{6}\) - \(\dfrac{9}{10}\) ) = \(\dfrac{1}{5}\) - x + ( \(\dfrac{1}{15}\) - \(\dfrac{-1}{5}\) )
Giúp mik nhanh với ạ .
tính tổng và hiệu của các dơn thức
a.-\(\dfrac{1}{3}\)\(\times\)\(x\)3y1và\(\dfrac{4}{3}\)\(\times\)\(\chi\)3y4
b.-2xyz và xyz