\(\left[{}\begin{matrix}\dfrac{3}{4}x-\dfrac{9}{16}=0\\\dfrac{1}{3}+-\dfrac{3}{5}:x=0\end{matrix}\right.\left[{}\begin{matrix}\dfrac{3}{4}x=\dfrac{9}{16}\\-\dfrac{3}{5}:x=-\dfrac{1}{3}\end{matrix}\right.\left[{}\begin{matrix}x=\dfrac{36}{48}\\x=-\dfrac{9}{5}\end{matrix}\right.\)
lâu rồi ko lm ko bt đúng ko
Ta có: \(\left(\dfrac{3}{4}x-\dfrac{9}{16}\right)\left(\dfrac{-3}{5}:x+\dfrac{1}{3}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{4}x-\dfrac{9}{16}=0\\\dfrac{-3}{5}:x+\dfrac{1}{3}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{4}x=\dfrac{9}{16}\\\dfrac{-3}{5}:x=\dfrac{-1}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=\dfrac{-3}{5}:\dfrac{-1}{3}=\dfrac{-3}{5}\cdot\dfrac{3}{-1}=\dfrac{9}{5}\end{matrix}\right.\)
