Question

\(\dfrac{7}{19}\) x \(\dfrac{8}{11}\) + \(\dfrac{3}{19}\) x \(\dfrac{7}{11}\) + \(-\dfrac{12}{19}\)

 

Answer 1

\(\dfrac{7}{19}\cdot\dfrac{8}{11}+\dfrac{3}{19}\cdot\dfrac{7}{11}-\dfrac{12}{19}\\ =\dfrac{8}{19}\cdot\dfrac{7}{11}+\dfrac{3}{19}\cdot\dfrac{7}{11}-\dfrac{12}{19}\\ =\dfrac{7}{11}\cdot\left(\dfrac{8}{19}+\dfrac{3}{19}\right)-\dfrac{12}{19}\\ =\dfrac{7}{11}\cdot\dfrac{11}{19}-\dfrac{12}{19}\\ =\dfrac{7}{19}-\dfrac{12}{19}\\ =\dfrac{-5}{19}\)

Answer 2

Answer 3

\(\dfrac{7}{19}.\dfrac{8}{11}+\dfrac{3}{19}.\dfrac{7}{11}+-\dfrac{12}{19}\)
\(=\dfrac{7}{11}.\dfrac{8}{19}+\dfrac{3}{19}.\dfrac{7}{11}-\dfrac{12}{19}\)
\(=\dfrac{7}{11}.\left(\dfrac{8}{19}+\dfrac{3}{19}\right)-\dfrac{12}{19}\)
\(=\dfrac{7}{11}.\dfrac{11}{19}-\dfrac{12}{19}\)
\(=\dfrac{7.1}{1.19}-\dfrac{12}{19}\)
\(=\dfrac{7}{19}-\dfrac{12}{19}\)
\(=\dfrac{-5}{19}\)