\(\dfrac{5}{3}\times\dfrac{15}{8}-\dfrac{9}{8}\times\dfrac{5}{8}-\dfrac{5}{3}\)
\(=\dfrac{5}{3}\times\left(\dfrac{15}{8}-\dfrac{9}{8}-1\right)\)
\(=\dfrac{5}{3}\times\left(\dfrac{15}{8}-\dfrac{9}{8}-\dfrac{8}{8}\right)\)
\(=\dfrac{5}{3}\times\dfrac{-1}{4}\)
\(=-\dfrac{5}{12}\)
\(\dfrac{15}{16}\div\dfrac{5}{8}\times\dfrac{3}{4}\)
\(\dfrac{21}{4}\times\dfrac{16}{14}\times\dfrac{1}{2}\times\dfrac{8}{3}\)
Tìm A biết: A\(\times\)(1-\(\dfrac{1}{4}\))\(\times\)(1-\(\dfrac{1}{9}\))\(\times\)(1-\(\dfrac{1}{16}\))\(\times\)(1-\(\dfrac{1}{25}\))=1\(\dfrac{3}{5}\)
\(\dfrac{12}{5}\times\dfrac{5}{9}-\dfrac{1}{3}\)
\(3\dfrac{7}{8}\times x-2\dfrac{3}{4}=3\dfrac{6}{12}\times\dfrac{10}{8}-\dfrac{1}{3}\)
cíuuuuuu
\(3\dfrac{7}{8}\times x-2\dfrac{3}{4}=3\dfrac{6}{12}\times\dfrac{10}{8}-\dfrac{1}{3}\)
Tìm x
A= 1\(\dfrac{1}{2}\) \(\times\)1\(\dfrac{1}{3}\) \(\times\)1\(\dfrac{1}{4}\) \(\times\)1\(\dfrac{1}{5}\) \(\times\).... \(\times\)1\(\dfrac{1}{2020}\) \(\times\) 1\(\dfrac{1}{2021}\)
\(\dfrac{7}{9}\times\dfrac{3}{5}\)
Tính giá trị biểu thức: A=29\(\dfrac{1}{2}\)\(\times\)\(\dfrac{2}{3}\)+39\(\dfrac{1}{3}\)\(\times\)\(\dfrac{3}{4}\)+\(\dfrac{5}{6}\)
(Nhớ rút gọn đến tối giản, trình bày theo cách của học sinh lớp 5)
tính
\(3\dfrac{1}{5}\times\dfrac{10}{11}+1\dfrac{2}{11}=\)
\(5\dfrac{1}{3}:1\dfrac{2}{3}-1\dfrac{1}{5}=\)
mik cần gấp mn 1
