\(\Leftrightarrow2\left(3x-7\right)=40\\ \Leftrightarrow3x-7=20\Leftrightarrow x=9\)
(3x - 7)2 = 8.5
6x - 14 - 40 = 0
6x - 54 = 0
x = 8
\(b,\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=-\left(\dfrac{7}{5}+\dfrac{7}{10}.x\right)\)
\(c,\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
\(d,\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
\(e,2\left(x-1\right)=\left(x-1\right)^2\)
1,4 . 3x-2 + 2 . 3x+1 = 4 . 34 + 2 . 37
2, \(\dfrac{3}{5}\) . 2x + \(\dfrac{7}{5}\) . 2x+3 = \(\dfrac{3}{5}\) . 210 + \(\dfrac{7}{5}\) . 213
3,\(\dfrac{5}{3}\) . 8x+2 - \(\dfrac{3}{5}\) . 8x = \(\dfrac{5}{3}\) . 811 - \(\dfrac{3}{5}\) . 89
4,(\(\dfrac{1}{2}\) - \(\dfrac{1}{6}\)).3x+4 - 4 . 3x = 316 - 4 . 319
Mn làm giúp em với ạ , em cảm ơn !
a. 7-4(x+1)=3x-5
c.\(\dfrac{5x+8}{3}=\dfrac{4-2x}{4}\) d. (9x-1)2=5
\(\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=\dfrac{7}{5}-\dfrac{7}{10}x\)
Tìm x:
a) \(\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
b) \(\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
1/Thực hiện phép tính:
𝒂) ( \(\dfrac{7}{5}\) − \(\dfrac{8}{7}\) ) + \(3\dfrac{2}{5}\) ∶ 𝟎,𝟔
b) \(\dfrac{11}{6}\) + \(\dfrac{7}{6}\) ∶ \(\dfrac{-5}{4}\)
c) \(\dfrac{7}{4}\) − \(\dfrac{5}{4}\) . \(\dfrac{8}{15}\)
2/ Tìm x biết
b) 𝒙 + 𝟐,𝟓 = \(\dfrac{-8}{3}\)
b) 𝟐𝒙 − 𝟐𝟎% = \(\dfrac{9}{5}\)
𝒄) ( \(\dfrac{5}{4}\) )2 + 𝒙 = \(2\dfrac{3}{4}\)
a) \(\dfrac{3x-7}{3}=\dfrac{-27}{7-3x}\)
b) \(\dfrac{3x+5}{12}=\dfrac{3}{5+3x}\)
a) \(2\dfrac{1}{2}\) - x + \(\dfrac{4}{5}\) = \(\dfrac{2}{3}\) - (\(-\dfrac{4}{7}\) )
b) \(-\dfrac{4}{7}\) - x = \(\dfrac{3}{5}\) - 2x
c) (\(\dfrac{3}{8}\) - \(\dfrac{1}{5}\) ) + (\(\dfrac{5}{8}\) - x) = \(\dfrac{1}{5}\)
\(\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-}{1\dfrac{1}{6}-}\dfrac{\dfrac{1}{4}}{\dfrac{7}{8}+}\dfrac{+\dfrac{1}{5}}{0,7}\)
