Question

1,4 . 3^x-2 + 2 . 3^x+1 = 4 . 3⁴ + 2 . 3⁷

^{2, \(\dfrac{3}{5}\) .} 2^x + \(\dfrac{7}{5}\) . 2^x+3 = \(\dfrac{3}{5}\) . 2¹⁰ + \(\dfrac{7}{5}\) . 2¹³

^{3,\(\dfrac{5}{3}\) .} 8^x+2 - \(\dfrac{3}{5}\) . 8^x = \(\dfrac{5}{3}\) . 8¹¹ - \(\dfrac{3}{5}\) . 8⁹

4,(\(\dfrac{1}{2}\) - \(\dfrac{1}{6}\)).3^x+4 - 4 . 3^x = 3¹⁶ - 4 . 3¹⁹

Mn làm giúp em với ạ , em cảm ơn !

Answer 1

4: \(\Leftrightarrow3^{x+4}\cdot\dfrac{1}{3}-4\cdot3^x=3^{16}\left(1-4\cdot3^3\right)\)
=>\(3^x\cdot27-4\cdot3^x=3^{16}\cdot\left(-107\right)\)

=>3^x*23=3^16*(-107)

=>\(x\in\varnothing\)

2: \(\Leftrightarrow2^x\left(\dfrac{3}{5}+\dfrac{7}{5}\cdot2^3\right)=2^{10}\left(\dfrac{3}{5}+\dfrac{7}{5}\cdot2^3\right)\)

=>2^x=2^10

=>x=10

3: \(\Leftrightarrow8^x\left(\dfrac{5}{3}\cdot8^2-\dfrac{3}{5}\right)=8^9\left(\dfrac{5}{3}\cdot8^2-\dfrac{3}{5}\right)\)

=>8^x=8^9

=>x=9

1: \(\Leftrightarrow3^x\cdot\left(4\cdot\dfrac{1}{9}+2\cdot3\right)=3^4\left(4+2\cdot3^3\right)\)

=>3^x=3^4*3^2

=>x=4+2=6